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*Most recent answer: 10/22/2007*

Q:

Can you calculate the rate at which water will flash to steam given the temperature and psia? For example, assuming approximately .8 PSIA and 100 degrees F, at what rate would the water evaporate? Would lowering the pressure or increasing the temperature change the evaporation rate significantly?Thanks.

- Rick Gresham (age 51)

Portland, OR, USA

A:

The answer is yes, the rate that water evaporates can indeed be calculated, but it depends on a few more things than you mention. The evaporation rate is influenced by 1) The temperature of the water at the air-water surface 2) The humidity of the air 3) The area of the air-water surface 4) The temperature of the air (more on this below) In a real-world situation of evaporating water, none of these four quantities above remains constant because the process of evaporation itself changes them. Water evaporating takes quite a lot of heat away -- 540 calories per gram -- when it evaporates. That’s enough to cool down 540 grams of water by a degree, or 50 grams of water a little more than ten degrees. If you are not very careful to replace the lost heat energy during the evaporation, the temperature will go down. And even then the temperature right at the surface will be lower than elsewhere in the water and it will depend on 5) water currents convecting heat and the ability to keep the temperature constant at 100 degrees F. For a similar reason, the air near the surface of the water will become more saturated with water as the water evaporates. The evaporation rate will depend on: 6) airflow past the water/air surface. These factors explain why: People sweat to stay cool. People say "It’s not the heat, it’s the humidity." (Video) EVAPORATE your Grey Tank Water and NEVER go to the DUMP STATION AGAIN! People use fans to keep themselves cool on hot days. Spraying a fine mist of water in the air will make it evaporate faster (increased total surface area). I am guessing your 0.8 PSIA is an indication of the partial pressure of water in the air, and that covers the humidity dependence mentioned above. Looking in a table of vapor-pressures (this tells me what the pressure of water vapor liquid water is in equilibrium with at different temperatures), I see that the vapor pressure of water at 100 degrees F is 0.96 pounds/square inch. If the vapor pressure is less than 0.8, the water would not evaporate at all, and in fact in that atmosphere, water would condense. Irving Langmuir developed a way to measure vapor pressure (mass loss rate)/(unit area) = (vapor pressure - ambient partial pressure)*sqrt( (molecular weight)/(2*pi*R*T) ) (from Zemansky and Dittman, Heat and Thermodynamics, McGraw Hill, copyright dates from 1937 to 1981 in my copy). The ambient partial pressure of water is the 0.8 PSI you gave me, and the vapor pressure is the 0.96 PSI (we’re going to have to convert this to different units to make it work out). T is the temperature in degrees Kelvin -- 310 degrees above absolute zero. R is the gas constant which is 8.314 Joules/(mol degree K). Naturally the units of measurement in formulas like these are a disaster. I would suggest using standard Metric (SI) units for everything. Multiply the pressures in PSI by 6895 to get pressurs in Pascals (Newtons/sq. M), and the molecular weight should be in kg/mol (to cancel out the moles in the gas constant R). For water this is 0.018 kg/mole. Doing the arithmetic gives a rather largeish number -- 1.1 kg per square meter per second. Keep in mind that this assumes that the temperature is maintained at 100 degrees at the interface and the the humidity is maintained right up to the interface, meaning that you have to blow air with a big fan at a high rate to carry away the evaporating water, and even this might not be enough (or you are in a near vacuum with only a tiny pressure of water vapor over the water), and also that there are no impurities on the water (a layer of oil will spoil the whole thing, and sweat contains lots of oils). A real situation involves the fact that the humidity near the interface is much higher than even a short distance away, and that the water vapor must diffuse away. This effect will slow the evaporation down quite a a lot because the evaporation rate is proportional to the difference between the vapor pressure and the partial pressure of the substance, and diffusion can only take water away so fast. As the water evaporates, the partial pressure of water in the gas right over the water will be nearly equal to the vapor pressure, and then it will drop as you go away from the surface, and how steeply this drops (which depends on the airflow rate and how long the water has been there evaporating) determines the rate at which water will diffuse away. Even with a fan blowing air past the surface, the process is limited by diffusion very close to the surface because a thin layer of air (called the "boundary layer") right next to the surface does not move relative to the surface. I won’t do the work on the diffusion because it depends too much on the details of the setup. The diffusion constant for Nitrogen is 0.185 cm**2/sec at room temperature and 1 atm. See Also solutions manual, test bank for Meteorology Today An Introduction to Weather, Climate, and the Environment, 2nd Canadian Edition, 2nd edition, 2e by Donald Ahrens, Peter Jackson, Chris Jackson10 Cheapest Accredited Online Colleges (Top 10 For 2022)A Guide to Artillery in Hell Let LooseTop Self-Paced Online Colleges & Courses for 2022Lowering the partial pressure of water will raise the evaporation rate as mentioned above. Lowering the air pressure will increase the diffusion rate. The partial pressure of water at 100 degrees F is so high in fact, that bubbles will form spontaneously in the fluid and cause it to boil rapidly if the water is placed in a vacuum (upsetting the surface area because of all of the bubbles). Increasing the temperature will increase the evaporation rate. It appears in the denominator (in the square root) above, but a much more important dependence comes in with the vapor pressure. vapor pressure is proportional to exp(-latent heat/RT) (F. Reif, Fundamentals of Statistical and Thermal Physics, McGraw Hill, 1965). The latent heat is the 540 cal/gram (watch the units again!). T again is in the absolute scale. Furthermore, as the temperature increases the diffusion rate increases too, but this is the temperature of the air, not the water -- hence the dependence on the air temperature I mentioned earlier. Tom |

*(published on 10/22/2007)*

## Follow-Up #1: water condensation rate

Q:

related question - what about condensation rate? Let"s say that instead of 0.8 PSIA we had 1.1 PSIA. The same calculation applies but with the direction reversed?

- John (age 21)

New York, NY, USA

A:

Yes, you're right. Unfortunately the complications still apply too. As water condenses, that leaves a depleted layer behind with less water vapor. How big an effect that is depends on how rapidly the atmosphere is stirred by winds, etc. Likewise as the vapor condenses it deposits energy in the top of the liquid, heating it up. How hot it gets (and hence how much evaporation results) depends on how well-stirred the liquid is.

Mike W.

*(published on 01/16/2008)*

## Follow-Up #2: liquid-vapor equilibrium

Q:

Another related question - evaporation rate in a closed container:Evaporation in a closed container will proceed only until there are as many molecules returning to the liquid as there are escaping (=saturated vapor pressure). Is there a appropriate equation to calculate the conditions for such a equilibrium state? For example, I want to find out wheter a small amount of a fluid in a relatively large container at a constant temperature of the fluid can be prevented from net evaporation by increasing the pressure of the ambient air/gas in the container or by reducing the size of the container or increasing the amount of the fluid, respectively.

- Marco W. (age 35)

Z? Switzerland

A:

Yes indeed there's an equation. It's called the Clapeyron equation, and for most conditions a simpler approximate version called the Clausius-Clapeyron equation works fine. The vapor pressure that's in equilibrium with the liquid depends strongly on the temperature, and the parameters in the equation are different for every substance.

Here's a link to a discussion of the equations: ,

These equations can also be found in any standard thermodynamics text.

The pressure obtained in the equation is the partial pressure due to the vapor from the liquid. Increasing the pressure of ambient air generally has very little effect, unless the liquid is made of the same molecules as the air, nitrogen or oxygen. So what one does is calculate the partial pressure at the given temperature, convert (using the ideal gas law pV=nRT, where p is pressure, V container volume, n moles of vapor, R the gas constant, T the absolute temperature) to figure out how many moles of vapor that would be. If the answer comes out smaller than the moles of liquid put in, the remaining liquid will be in equilibrium with the vapor. If it comes out bigger, what will happen instead is that all the liquid will vaporize.

Mike W.

*(published on 03/09/2008)*

## Follow-Up #3: ideal evaporation rate

Q:

Your answer to calculating the evaporation rate of water is of great interest to us, but you cite Zemansky and Dittman, Heat and Thermodynamics as your source. But I have that book (7th edition) and cannot find the equation or derivation. Can you tell me where to find the equation ? And can you clarify how to find the ambient partial pressure ? Is this equation valid for water below the boiling point ?Thanks.

- Paul (age 65)

Boonville, CA, USA

A:

Paul- I'll give a partial answer, without taking the time to track down the source of the equation.

If you look at this equation, what it's saying is that the rate at which mass is leaving the liquid when there's no vapor above the liquid is equal to the equilibrium mass density of the vapor times a typical thermal speed of one of the molecules, with a numerical factor thrown in that comes from averaging over all the directions the molecules can be moving. When there is some vapor already above the liquid, the net rate is reduced by whatever fraction of the equilibrium pressure that ambient partial pressure is. If the ambient partial pressure is already equal to the equilibrium pressure, the net rate is zero- as many molecules go from vapor to liquid as go the other way.

So the equation makes sense. In equilibrium, the rate at which molecules leave the surface is the same as the rate that they enter the surface. But you can calculate that entrance rate by assuming that the molecules in the equilibrium gas are moving with random thermal speeds. There are two simple assumptions made here- that the vapor forms a classical ideal gas (usually true) and that when a molecule from the vapor hits the liquid the chance it sticks is 100%, which I guess is pretty close to true.

The equation should work fine for water below the boiling point. However, in using this equation there's one thing you have to be very careful about. If there's no wind, the ambient partial pressure near the surface builds up to nearly the equilibrium value, so the net evaporation rate drops. How far it stays below equilibrium depends on the wind, which has no fundamental equation. You're also assuming that the evaporation rate isn't so large as to cool the surface much. That depends largely on whether the liquid is well-stirred, again not described by some fundamental equation.

As for what the ambient partial pressure is far from the surface, that's just the equilibrium vapor pressure times the relative humidity (for water), by definition of relative humidity. There's no basic equation to tell you what the relative humidity should be. It depends on what's happening with the weather. You can get instruments that will measure it, or check a weather report.

Mike W.

*(published on 05/04/2009)*

## Follow-Up #4: Swimming pool evaporation rate

Q:

Our town is considering building a new municipal swimming pool. Part of the argument (at a recent public forum on the topic) for needing a new pool is the city officials telling us that our 240,000 gal. pool is losing 70,000 gal. every day. A woman behind me asked the question, "How much is lost from evaporation?" Is it possible for a layman to calculate a correct order-of-magnitude value for our pool's evaporation? What measurements and equations would a person need?

- Jim Rasmussen (age 52)

Hampton, IA US

A:

Hello Jim,

We get questions like this frequently. It's a toughie. The answer depends on a number of parameters: surface area, temperature, wind speed, humidity, etc. There are so many variables that there is no simple (or even complicated) formula. The best way to determine the answer is to perform a simple experiment. Get a bucketful of water from the pool, let it sit for 24 hours and then measure the drop in the level of water. You can make a pretty good estimate of your local evaporation rate by multiplying by the ratio of surface areas of the pool and bucket, times the volume of water that has evaporated from the bucket.

It does seem, however, that 70,000 gallons a day is a bit much for evaporation. I'd really look for some other mechanism, leakage, splash over, or...

Here is a web site that explains the experiment I suggested in greater detail. Good luck.

LeeH

*(published on 06/21/2009)*

## Follow-Up #5: evaporation rate expression

Q:

The equation listed on this page for the mass loss rate:(mass loss rate)/(unit area) = (vapor pressure - ambient partial pressure)*sqrt( (molecular weight)/(2*pi*R*T) ) appears to be incorrect.This equation implies that the mass loss rate is proportional to sqrt(1/T). If this is the case, then as the temperature increases the mass loss rate decreases. This is not true.

- Joe Atherton

UK

A:

Whoops. We posted that comment from a reader without checking. On further consideration, we didn't even check what the expression was intended to equal.

However, if you'll note, the equation also includes the saturation vapor pressure. Even if the saturation vapor density N/V weren't increasing with T (it is), the ideal gas law p=NkT/V would say that the expression would come out an increasing function of T.

In fact, if you include that (and assume the initial vapor pressure is zero) one gets about sqrt(kT/m) N/V, where N/V is the saturation molecular concentration in the vapor. (I'm not worrying here about the numerical factor). So that is essentially the typical thermal speed times the concentration of molecules. That should be the evaporation rate in units of molecules/(area*time).

p.s. In the various notes sent in, there were two forms of the equation. One, described here, gives the number lost per area*time. The other includes an extra factor of m and gives the mass loss per area*time.

Mike W.

*(published on 06/28/2010)*

## Follow-Up #6: source of evaporation rate equation

Q:

In regards to the source of the equation, I believe the original work can be traced back to this reference: "Evaporation and surface structure of liquids". By G. Wyllie. Published in Proc. R. Soc. Lond. A. 1949, 197, pp. 383-395. The equation they report in this paper is: (2pi*mkT)^(-1/2) * (saturation vapour pressure - actual pressure) where m is the molecule's mass, k is botzmann's constant, and T is the temp in Kelvin. The units work out to (1 / sq meters * seconds)

- Scott (age 29)

Tucson, az

A:

Thanks!

Mike W.

*(published on 07/29/2010)*

## Follow-Up #7: dehumidifiers and water damage

Q:

There is a debate in the water damage restoration world. Does a dehumidifier, by taking water vapor out of the air, create evaporation in structural materials that have been water damaged?Is evaporation only created by heat?I have seen equations for calculating the evaporation rate, is humidity the part of the equation that slows down that rate or does lowering the humdity actually create evaporation?

- Ben Justesen (age 32)

Moses Lake, WA, USA

A:

That's an interesting question. Evaporation, in the sense of water molecules leaving the surface, will happen all the time. What you guys care about, however, is net evaporation, the difference between the bare rate of water molecules leaving and the rate of others coming in from the air to the surface. Drying out the air increases the net evaporation rate by reducing the rate at which molecules come in from the air.

All the evaporation requires heat, because it take energy to break a water molecule away from the stuff it's stuck to. Even at room temperature, that heat can flow in from the surroundings. The rate at which the water molecules break loose is very sensitive to temperature, so the people who say you need to heat things up have a very good point. If you want the drying to occur fast enough to avoid much mold growth, etc., then heating things up is a big help. Running dehumidifiers also helps, as I mentioned, but even if the air is perfectly dry, that can't get the net rate any higher than the bare evaporation rate, which is highly temperature sensitive.

Mike W.

*(published on 10/17/2011)*

## Follow-Up #8: sunlight and evaporation

Q:

I'm an engineer (did research in Urbana). I also studied Meteorology. But I wanted to get some additional insight into some “claims” over water evaporating from a man-made canal essentially due to the effects of direct sunlight. (From what I understand, water evaporation is subject to air temp vs water temp, air humidity, air flow rate as well as the surface area of the water and the turbulent flow rate of the water.) So, there has been significant politically motivated drama surrounding a Canal Top Solar Field in India (the land of hot and dry air) where, loosely covering a man-made water canal (maybe 10 meters wide) can save about 9 million liters of water (2.5 mil gals) per year. This is claimed to be … only by covering less than 1 km of a 458 km long canal. (If you perform a web search, you will see that the solar panel field is raised above the surface where air can generously flow around the water.) My question is whether the claim of loosely covering a small section of flowing water (1.7 m/s) can save up to 2.5 million gallons of water per year or whether this is huge political drama? (I guess the bigger question is asking if sunlight directly heats up water or only water particulate and flow bed surfaces?) Please let me know your thoughts.

- Sunny (age 30)

Sacramento, CA

A:

This estimate actually looks very realistic to me, based on a crude calculation. Although all the factors you mention do show up in the net water evaporation rate, the key point is that for every kg of water that evaporates there must be a net heat flow of about 2MJ into the water to supply the latent heat. The sunlight (say 1000 W/m^{2}) hitting that 10^{4}m^{2}will supply a lot of energy. Some, mostly infrared, will be directly absorbed by the water. A lot of the visible light will be absorbed by those rocks at the canal bottom, and most of that heat should then be transferred to the flowing water, although some will diffuse out into the ground underneath. Within the rather large error bars of my ignorance of the details of the sunlight pattern in the area, the color of the rocks, etc., that 2.5 M gal/year sounds just about right.

This is purely a matter of keeping that extra energy from getting into the water, and makes no assumption that the flow of air over the water is reduced at all.

Mike W.

*(published on 09/22/2013)*

## Follow-Up #9: science fair question on water evaporation rate

Q:

I am doing my research for the science fair, and my question was does water evaporate the fastest in dirt, sand, or by itself. Can you think of a way that I can guess an accurate answer without doing the experiment?

- jaden (age 11)

Irvine, CA, USA

A:

No, I can't think of a good way to guess. Here's a few of the complications that make it hard. A plain water surface allows the wind to blow on it directly. That might help speed up evaporation. Sand has lots of little crevices that might partly fill up, increasing the surface area. That might speed evaporation. Dirt might have a rough wet surface, also increasing surface area and increasing the evaporation rate. But maybe the dirt is mostly some clay with a smooth surface, and that might reduce evaporation.

Experiments are great things!

Mike W.

posted without checking by Lee until he returns from Paris

*(published on 10/14/2013)*

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## FAQs

### What is the rate of water evaporation? ›

On average a water feature will lose **½% to 1% of the gallons pumped per hour in a day**.

**How do you measure evaporation rate? ›**

Currently, **pan evaporimeters** – resembling large pans that are filled with water – are the most commonly used devices to measure evaporation rates. The change in water level over a day gives the evaporation rate from that area for that day.

**What affects the rate of water evaporation? ›**

**Temperature: The greater the temperature of the liquid and its surroundings, the faster the rate of evaporation.** **Surface area occupied by the liquid**: Since evaporation is a surface phenomenon, the greater the surface area occupied by the liquid, the quicker it undergoes evaporation.

**How does water evaporate at less than 100? ›**

These are relatively weak, and there are always some **H _{2}O molecules whizzing around with enough energy to break free of their neighbours**, even at temperatures well below 100°C. These can then escape – 'evaporate' – into the air.

**What is evaporation answer? ›**

Evaporation is **the process by which a liquid turns into a gas**. It is also one of the three main steps in the global water cycle.

**What is evaporation of water? ›**

Evaporation is **the process that changes liquid water to gaseous water (water vapor)**. Water moves from the Earth's surface to the atmosphere via evaporation. Evaporation occurs when energy (heat) forces the bonds that hold water molecules together to break.

**What is the unit of rate of evaporation? ›**

The rate of evaporation is defined as the amount of water evaporated from a unit **surface area per unit of time**. It can be expressed as the mass or volume of liquid water evaporated per area in unit of time, usually as the equivalent depth of liquid water evaporated per unit of time from the whole area.

**What is used to measure evaporation? ›**

**An atmometer or evaporimeter** is a scientific instrument used for measuring the rate of water evaporation from a wet surface to the atmosphere.

**What is evaporation give example? ›**

Evaporation is described as the phase in which the water state takes place from the liquid to the gaseous or vapour state. An example of evaporation is the **melting of a cube of ice**.

**How can you make water evaporate faster? ›**

Water evaporates faster **when it is warm than when it is cold**. If you spread out something that is drying, there is more area for the water to evaporate from. This makes evaporation faster.

### What are 3 factors that affect the rate of evaporation of water? ›

**Three factors on which affect the rate of evaporation of a liquid:**

- Area of exposed surface.
- Temperature of liquid.
- Nature of the liquid.
- Presence of humidity.

**How does pressure affect rate of evaporation? ›**

Evaporation is a surface phenomenon in which surface molecules of solution moves to the atmosphere. If atmospheric pressure is increased then due to external pressure molecules on the surface will not move to the atmosphere so if atmospheric pressure increases, a rate of evaporation decreases.

**How fast does water evaporate at 30 degrees? ›**

At 30° C, the same values are respectively **6.8 mm/day**, 9.6 mm/day, 12.9mm/day, when the wind blows at 0, 2m/s and 9m/s."

**How long does it take for water to evaporate? ›**

According to these web sites, the average time a water molecule spends in the atmosphere is **8-9 days**. This is pretty fast! So on average, it takes just 8-9 days for a water molecule to evaporate, enter the atmosphere, and then leave it again as rain.

**Does water only evaporate at 100 degrees? ›**

**False,Water does not “evaporate” at 100°C**, it “boils”. Water can evaporate at any temperature, the rate of evaporation depending on the temperature and the humidity in air. Boiling is when evaporation is super fast, and ALL the water has to becomes gaseous.

**What causes evaporation? ›**

Evaporation causes **cooling**. Because in evaporation the water changes form liquid to vapour state so the vapour of water causes the surface to becomes cool. Evaporation causes cooling because during evaporation the particle of the liqued absord energy from the surroundings to regain the energy lost during evaporation.

**What is evaporation Class 3 Short answer? ›**

“Evaporation”

**The conversion of water from a liquid to a gas**. Solar energy drives evaporation of water from the ocean. The evaporated water changes from a liquid form into water vapor a gaseous form.

**Does water evaporate fast? ›**

Water in a very tall container with a small top surface takes much longer to evaporate than water in a large, shallow container. **If the surface area is so large that the water is only one molecule deep, it evaporates almost immediately**.

**Do all liquids evaporate? ›**

**All liquids (and even solids) evaporate** in the sense that some of their molecules or atoms fly off the surface into the nearby gas. If something blows those molecules away, then more will keep evaporating until the liquid is gone.

**Why is evaporation very important? ›**

Evaporation, mostly from the oceans and from vegetation, replenishes the humidity of the air. It is an important part of the exchange of energy in the Earth-atmosphere system that produces atmospheric motion and therefore weather and climate.

### What does an evaporation rate mean? ›

The evaporation rate is **the ratio of the time required to evaporate a test solvent to the time required to evaporate the reference solvent under identical conditions**. The results can be expressed either as the percentage evaporated within certain time frame, the time to evaporate a specified amount, or a relative rate.

**What does a high evaporation rate mean? ›**

Evaporation rates are higher at higher temperatures because **as temperature increases, the amount of energy necessary for evaporation decreases**. In sunny, warm weather the loss of water by evaporation is greater than in cloudy and cool weather.

**Why is rate of evaporation constant? ›**

**There is a dynamic equilibrium and the number density of the vapour molecules stays constant** and the pressure exerted by the vapour is called the saturated vapour pressure. Show activity on this post. The rate of evaporation is faster in the beginning and the rate gradually decreases till it reaches equilibrium.

**Which instrument do we use to measure water? ›**

hydrometer, device for measuring some characteristics of a liquid, such as its density (weight per unit volume) or specific gravity (weight per unit volume compared with water).

**How do you calculate evaporation rate from a evaporation pan? ›**

calculate actual evaporation by **multiplying pan evaporation with pan factor (0.8)**. There should not be any leakage of water from the pan. Pan should always be placed 10 cm above the ground surface.

**What is the instrument used to measure water? ›**

**A water flow meter** is an instrument capable of measuring the amount of water passing through a pipe.

**Where is evaporation used? ›**

The evaporation process is used in **food processing industries to process milk, pasta, and other concentrates**. Salt crystals obtained either from a natural process or from an industrial process, evaporation is used. The melting of an ice cube is an example of evaporation.

**Is boiling water evaporation? ›**

When water is heated it evaporates, which means it turns into water vapor and expands. At 100℃ it boils, thus rapidly evaporating. And at boiling point, the invisible gas of steam is created. The opposite of evaporation is condensation, which is when water vapor condenses back into tiny droplets of water.

**How long does it take to evaporate 1 Litre of water? ›**

Since the mass of room temp water = approx. 1Kg, this means it would take approx. 7,500 watts-hours to completely evaporate 1 liter of water in **5 minutes**.

**How fast does water evaporate from a pool? ›**

The average pool water evaporation rate is **about a quarter of an inch of water per day or more than two inches in a week**, which on a 33′ x 18′ swimming pool (an average pool size) is more than 2500 liters or approximately 600 gallons a week; this may vary depending on your climate and the factors listed above.

### How fast does water evaporate at 30 degrees? ›

At 30° C, the same values are respectively **6.8 mm/day**, 9.6 mm/day, 12.9mm/day, when the wind blows at 0, 2m/s and 9m/s."

**How much water evaporates from the ocean each day? ›**

To answer your question, roughly **1400 cubic kilometers** (1.4 x 10^15 liters) of water is evaporated each day on earth.

**What is the fastest way to evaporate water? ›**

**Heating a liquid** causes the water molecules to move faster which makes evaporation happen faster.

**Does cold water evaporate faster than hot? ›**

Water is made up of tiny molecules that are always moving around. The constant movement builds up energy that eventually causes water to evaporate. However, **cold water will evaporate much slower than it would if it was hot**. When water is hot, the molecules move much faster leading to a quicker evaporation.

**How quickly does hot water evaporate? ›**

If we boil water it takes, for example, 5 minutes to reach the boiling point. If we continue heating, it will take another **20 minutes or so** before the water has completely evaporated (which is good, because it gives us time to save our kettle).

**Does water evaporate at night? ›**

Heat increases the rate of evaporation (**yes, even at night**), so you should expect your water to evaporate faster if you live in a warm climate, and slower if you live in a cold climate.

**How much water does a pool lose per day? ›**

What is the normal evaporation in a swimming pool? Generally speaking, pools lose approximately **1/4”** of water per day on average, though this can vary due to factors like wind, temperature, humidity and of course, the pool's total surface area.

**How much water will evaporate from a pool in the winter? ›**

An uncovered pool will lose water in the winter to evaporation in the same way it does during the summer. But the water loss is only **about a quarter-inch on average** during a 24-hour period when the pool is not in use. An uncovered or covered pool can have problems in the plumbing lines or pump.

**How long does it take to evaporate 50 mL of water? ›**

50 mL of water takes **5 min** to evaporate from a vessel on a heater connected to an electric source which delivers 400 W. The enthalpy of vaporisation of water is A 40.3 kJ per mol B 43.2 kJ per mol C 16.7 kJ per mol D 180.4 kJ per mol.

**Does moving water evaporate faster? ›**

Answer 1: **Yes, moving water can evaporate faster than still water**. When water moves, the molecules rub against each other and this will make the water warmer over time. The higher temperature will make the water evaporate more quickly.

### How can I evaporate water without heat? ›

Boiling Water Without Heat | Earth Lab - YouTube

**How much water evaporates in the world? ›**

In a 100-year period, a water molecule spends 98 years in the ocean, 20 months as ice, about 2 weeks in lakes and rivers, and less than a week in the atmosphere. **Each day the sun evaporates 1,000,000,000,000 (a trillion) tons of water**.

**How much water does the Earth lose per day? ›**

The current loss figure is equivalent ~**25,920 liters per day**, or 9,467 m3 per year.

**Will the oceans ever dry up? ›**

**The oceans aren't going to dry up**. At least not any time soon, so no need to add it to the list of things to worry about. But, what would our planet look like if they did?